$ y = 0 \Rightarrow x = 0 $

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• Factor out $ y $:
• y(y^2 - 5y + 6) = 0 \Rightarrow y(y - 2)(y - 3) = 0
• So the solutions for $ y $ are $ y = 0, 2, 3 $. Since $ x = y^2 $, the corresponding $ x $-values are:
• $ y = 2 \Rightarrow x = 4 $
• $ y = 3 \Rightarrow x = 9 $
• All roots are non-negative. The sum of the roots is $ 0 + 4 + 9 = 13 $.

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