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/ \[ 2a + b = 6 \]
\[ 2a + b = 6 \]
February 22, 2026
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\( a + b = 5 \)
\( 4a + 2b = 12 \)
Divide the second equation by 2:
Subtract the first equation from this:
\[ (2a + b) - (a + b) = 6 - 5 \]
Substitute \( a = 1 \) into \( a + b = 5 \):
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