1 north 4th

404
1.1.1.1 .
2011 1
n-1nn \dfrac {\ln \left ( n\right) -\ln \left ( n-1\right) } {n-\left ( n-1\right) } \left ( \ln n\right).
1+1=2 1 0 0
0405 vs4-1
2011 1 .
.
HappyHorse-1.0 4 HappyHorse-1.0 AI Artificial.
2025-11-11

404
1.1.1.1 .
2011 1
n-1nn \dfrac {\ln \left ( n\right) -\ln \left ( n-1\right) } {n-\left ( n-1\right) } \left ( \ln n\right).
1+1=2 1 0 0
0405 vs4-1
2011 1 .
.
HappyHorse-1.0 4 HappyHorse-1.0 AI Artificial.
2025-11-11
We begin by expanding both squared terms:
This expression is constant for all $ heta$, so its minimum value is simply:
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